If p,q,r are the roots of the polynomial a x 3 + b x 2 + c x - d = 0
Then (x - p) =0
(x - q) =0
(x - r) = 0
p + q + r = -b /a
p q +q r + r p = c/a
p q r = d/a
Let us suppose the equation
x3 - 9 x2 + 26 x - 24 = 0 and three roots are 2,3,4
sum of the three roots 2 +3 +4 = 9
from the equation - (-9/1) = 9
2 *3 + 3*4+4*2 = 26
from the equation c/a = 26
Product of the three roots = 2*3*4 = 24
from the equation -(-24/1)= 24
ABOVE RULES ARE USED IN SO MANY SUMS . MEMORIZE AND PRACTICE SINCERELY
Then (x - p) =0
(x - q) =0
(x - r) = 0
p + q + r = -b /a
p q +q r + r p = c/a
p q r = d/a
Let us suppose the equation
x3 - 9 x2 + 26 x - 24 = 0 and three roots are 2,3,4
sum of the three roots 2 +3 +4 = 9
from the equation - (-9/1) = 9
2 *3 + 3*4+4*2 = 26
from the equation c/a = 26
Product of the three roots = 2*3*4 = 24
from the equation -(-24/1)= 24
ABOVE RULES ARE USED IN SO MANY SUMS . MEMORIZE AND PRACTICE SINCERELY
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