problem
In an examination total students appeared are 40% girls and rest boys. Now 80% of the boys and 60% of the girls has succeeded in examination. How many % of the total have failed in the examination.
Solution:
When 40 % are the girls , so 60 % are boys. { In totality it is 100%}
When the answer is asking in % number, let us assume that total no os girls and boys are 100.
Now what is happening that out of 60 boys, 80% of the boys have passed.
No of boys have passed is = 60* 80/100 = 48 No of boys or 48 % of boys have passed.
No of girls passed is = 40* 60/100 = 24 % of the girls have passed.
so no of boys and girls failed = 100 - (48 + 24) = 28%
Other problem
In a school 83 % of students passed in mathematics, 79% students passed in English, 75% students passed in both the subjects and if total of students failed is 26. Find the total no of students.
Solution
83% or 83 no of students passed in mathematics.
So students passed in mathematics but failed in english = 83- 75= 8%
Similarly students passed in english but failed in mathematics = 79-75= 4%
So the students who have passed in one subject and both subjects are 75 +4+8= 87%
and students failed 100- 87= 13%
Now 13% of the total students are 26
Total no of students are 26* 100/13 = 200 nos.
Aklbert buys 4 horses and 9 cows for Rs. 56,00000.00 . If he sells the horses at 10 % profit and cows with 20 % profit , then he earns a total profit of Rs.60000.00 . The cost of the horse and the cows.
Solution:
4x + 9y = 5600000.________ (1)
4* (x+ 10/100*x) + 9 * (y+ 20/100 *y) = 56000000 + 600000_________(2)
Another problem in percentage
A person gives 12 % additional discount on the discounted price after giving an initial discount on 20 % .If the final sale price is Rs. 5400.00 what it is labelled price?
Let us start the math backwardly.
Final sale price is Rs. 5400.00
He gave additional discount of 12 %
Before giving the discount price was Rs. 5400.00 + 12 % of 5400= Rs 6048.00
This price is already a discounted one by 20%
The price will be adding this discount = 6048 + 20% of 6048
= 6048 + 20/100 * 6048
=7257.60
the actual price before the discounting was Rs. 7257.60
another problem SBI PO 2000
a shopkeeper sells 25 articles at Rs. 45 per article after giving 10 % discount and earns 50 % profit. If the discount is not given the profit gained ?
No of articles does not bear any significance in percentage computation as all are computed in 100
At Rs. 45 he earns 50 % profit.
So his cost price is = Rs 45 - (50/100)45 =Rs. 22.5
Now at Rs. 45 he gave 10 % discount , if he did not give the discount price will be 45 + (10/100)*45 = Rs.49.50
Now at cost price of Rs 22.50 , selling price is Rs. 49.50
Profit= 49.50 -22.50 =Rs.27.00
profit percentage= 27/22.50 *100
A shopkeeper sold sarees at RS 266 each after giving 5 % discount on labelled price . Had he not given the discount , he would have earned a profit of 12 % on the cost price . What was the cost price. (sbi po 1999)
If labelled price is X then 5% discount of Rs X is 266
x- (5/100)*x = 266
or 0.95 x = 266
or x = 280
Now the condition is the at Rs 280 he will earn 12 % profit above cost price
let cost price be Rs. y
Then, y + 12 % y = 280
or y + 0.12 Y = 280
or 1.12 Y =280
or y= Rs. 250
In an examination total students appeared are 40% girls and rest boys. Now 80% of the boys and 60% of the girls has succeeded in examination. How many % of the total have failed in the examination.
Solution:
When 40 % are the girls , so 60 % are boys. { In totality it is 100%}
When the answer is asking in % number, let us assume that total no os girls and boys are 100.
Now what is happening that out of 60 boys, 80% of the boys have passed.
No of boys have passed is = 60* 80/100 = 48 No of boys or 48 % of boys have passed.
No of girls passed is = 40* 60/100 = 24 % of the girls have passed.
so no of boys and girls failed = 100 - (48 + 24) = 28%
Other problem
In a school 83 % of students passed in mathematics, 79% students passed in English, 75% students passed in both the subjects and if total of students failed is 26. Find the total no of students.
Solution
83% or 83 no of students passed in mathematics.
So students passed in mathematics but failed in english = 83- 75= 8%
Similarly students passed in english but failed in mathematics = 79-75= 4%
So the students who have passed in one subject and both subjects are 75 +4+8= 87%
and students failed 100- 87= 13%
Now 13% of the total students are 26
Total no of students are 26* 100/13 = 200 nos.
Aklbert buys 4 horses and 9 cows for Rs. 56,00000.00 . If he sells the horses at 10 % profit and cows with 20 % profit , then he earns a total profit of Rs.60000.00 . The cost of the horse and the cows.
Solution:
4x + 9y = 5600000.________ (1)
4* (x+ 10/100*x) + 9 * (y+ 20/100 *y) = 56000000 + 600000_________(2)
Another problem in percentage
A person gives 12 % additional discount on the discounted price after giving an initial discount on 20 % .If the final sale price is Rs. 5400.00 what it is labelled price?
Let us start the math backwardly.
Final sale price is Rs. 5400.00
He gave additional discount of 12 %
Before giving the discount price was Rs. 5400.00 + 12 % of 5400= Rs 6048.00
This price is already a discounted one by 20%
The price will be adding this discount = 6048 + 20% of 6048
= 6048 + 20/100 * 6048
=7257.60
the actual price before the discounting was Rs. 7257.60
another problem SBI PO 2000
a shopkeeper sells 25 articles at Rs. 45 per article after giving 10 % discount and earns 50 % profit. If the discount is not given the profit gained ?
No of articles does not bear any significance in percentage computation as all are computed in 100
At Rs. 45 he earns 50 % profit.
So his cost price is = Rs 45 - (50/100)45 =Rs. 22.5
Now at Rs. 45 he gave 10 % discount , if he did not give the discount price will be 45 + (10/100)*45 = Rs.49.50
Now at cost price of Rs 22.50 , selling price is Rs. 49.50
Profit= 49.50 -22.50 =Rs.27.00
profit percentage= 27/22.50 *100
A shopkeeper sold sarees at RS 266 each after giving 5 % discount on labelled price . Had he not given the discount , he would have earned a profit of 12 % on the cost price . What was the cost price. (sbi po 1999)
If labelled price is X then 5% discount of Rs X is 266
x- (5/100)*x = 266
or 0.95 x = 266
or x = 280
Now the condition is the at Rs 280 he will earn 12 % profit above cost price
let cost price be Rs. y
Then, y + 12 % y = 280
or y + 0.12 Y = 280
or 1.12 Y =280
or y= Rs. 250
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